1. Segment the piece into groups of notes called sets. They can be grouped by such categories as pitch,
rhythm, phrasing, register, timbre, etc
(Bb,A,C,B)
2. Put the set in Normal Order.
á Pitches
must appear in ascending order
á Interval framing the set must be the smallest possible.
á
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(9,10,11,0)
3. Breaking a tie.
NO TIE
4. Put set in Prime Form.
To get the 9 to 0 either add 3 or subtract 9
|
|
9 |
10 |
11 |
0 |
|
-9 or +3 |
0 |
1 |
2 |
3 |
5. Determine the Vector.
|
|
0 |
1 |
2 |
3 |
|
-1 |
|
0 |
1 |
2 |
|
-2 |
|
|
0 |
1 |
|
-3 |
|
|
|
0 |
6. Count up Interval Classes to determine interval content. The six interval classes are:
Interval Class 1Ñ1or 11 (m2/M7)
Interval Class 2Ñ2 0r 10 (M2/m7
Interval Class 3Ñ3 or 9 (m3/M6)
Interval Class 4Ñ4 or 8 (M3/m6)
Interval Class 5Ñ5 or 7 (P4/P5)
Interval Class 6Ñ6 (TT)
|
1(11) |
2(10) |
3(9) |
4(8) |
5(7) |
6 |
|
3 |
2 |
1 |
0 |
0 |
0 |
This Vector is: [3 2 1 0 0 0]
7. Look up the Set Class number
4 Ð 1
Hanson Analysis Ð All the intervals above A, then Bb, then, B.
A Ð Bb = m2 Ð d ; A Ð B = M2 Ð s ; A Ð C = m3 Ð n
Bb Ð B = m2 Ð d ; Bb Ð C = M2 Ð s
B Ð C = m2 Ð d
Answer:
n,s2d3 a very dissonant chord!!!